Встроенное ядро LR33300
В состав CPU входит ядро LSI LR33300.
Естественно оно равномерно размазано по чипу, наряду с другими компонентами :-)
Доподлинно известно (из тестов и хакерских доков), что у сопроцессора 0 кастрирован MMU, при этом виртуальный адрес преобразуется в физический просто обнулением трёх старших разрядов.
- I-Cache is 4k long
- Divided into 16-byte "lines"
- 4 instruction per line
- Each line has a "tag" indicating which physical address is cached
- Instruction reads check tag to see if code is in cache
- Code position in I-cache depends on low-order 12-bits of address
- Code may wrap from end of cache to beginning
- High nybble of instruction address controls if code is cacheable
- Instruction reads from cache take 1 tick
If instruction not in cache, the appropriate cache line is burst filled from RAM:
- Takes 4-7 ticks to read from RAM
- Plus 1 tick to transfer from cache to R3000
- Reads entire line in 1 burst
Code may wrap from end of cache to beginning withot penalty. Execution continues at start of cache.
- Memory Addresses: 0x80051F34 ... 0x80052233
- Cache Addresses: 0xF34 ... 0xFFF -> wrap -> 0x000 ... 0x233
High nybble of instruction address controls if code is cacheable:
- 0x8 & 0x0 - Cacheable
- 0xA - Not Cacheable
- D-Cache (aka Scratchpad) is 1K long
- Memory mapped : address range 0x1F800000 ... 0x1F8003FF
- 1 tick read/write access.
- RAM writes normally 3 to 6 ticks
- RAM reads normally 2 to 6 ticks
- Cannot be used for DMA transfers
Memory Page Faults
Memory pages are 1k long, on 1k boundaries:
- 0x000 ... 0x3FF, 0x400 ... 0x7FF etc.
Page faults occur when you read or write a different page from the previous read / or write operation. Burst reads to I-cache can cause page fault. D-cache reads & writes don't cause page fault.
Page faults slow down RAM Reading access:
- 1st read from particular page in RAM takes 5 ticks: 4 ticks for RAM to R3000 R-buffer, 1 tick R-buffer to CPU
- 2nd & subsequent reads take just 2 ticks : 1 tick for RAM to R3000 R-buffer, 1 tick R-buffer to CPU.
- True for both data reads and I-cache burst read.
Page faults slow down RAM Writing access:
- 1st write to a particular page in RAM takes 5 ticks: 1 tick for CPU to R3000 W-buffer, 4 ticks W-buffer to RAM
- 2nd & subsequent writes take just 3 ticks: 1 tick for CPU to R3000 W-buffer, 2 ticks W-buffer to RAM
R3000 CPU has "Write-buffer" between registers and main RAM. W-buffer is four step 32bit length fifo. It takes one cycle to write to W-buffer. But if there are no free register on W-buffer, CPU must flush W-buffer, write ALL the data on W-buffer to main RAM. It takes one or four cycles to write a data on W-buffer to main RAM. If two or more write operations are done continuously, the first operation takes four cycles and the second and later operations take only one cycle. And main RAM has 1KByte "pages". Any write operation on new page takes four cycles. And programmer cannot control or detect the W-buffer flush timing, and cannot know the status of it. R3000 has Bus-Snoop-Mechanism and I-cache. You cannot predict the start of flushing of W-buffer, even if you know the complete assembler codes. Each step of W-buffer is assigned to one store instruction. So if four Store-Byte-Instructions are executed, W-buffer becomes full.
В вики нашёл, но больше смахивает на какую-то лажу. Последний MUX например вообще без управления.